Question

Mx and My denote the atomic masses of the parent and the daughter nuclei respectively in a radioactive decay. The Q-value for a β – decay is Q1 and that for a β + decay is Q2. If me denotes the mass of an electron, then which of the following statements is correct?
(a) Q1 = (Mx – My) c2 and Q2 = (Mx – My) – 2me))c2
(b) Q1 = (Mx – My) c2 and Q2 = (Mx – My))c2
(c) Q1 = (Mx – My – 2me) c2 and Q2 = (Mx – My) + 2 me)c2
(d) Q1 = (Mx – My + 2me) c2 and Q2 = (Mx – My) + 2 me)c2

Answer 1

Thus q = ( Mx - My - 2m ) and c2 and Q2 = (Mx – My) + 2 me)c2

Option (C) is correct.

Explanation:

• In bets B+ decay the nucleus loses positive (+ve) charge making it less positive.
• The electron cloud must lose a negative charge to keep the atom neutral.
• Overall 2 electrons have been lost by the atom.
• One from the nucleus and the other one from the cloud.
• Therefore q = ( Mx - My - 2m ) c^2 and Q2 = (Mx – My) + 2 me)c^2

Answer 2

Explanation:

Explanation:

Characteristics of the image form by the plane mirror are:

Since the image form by the plane mirror has magnification is 1 then,

(I). The size of the image form will be the same as the size of the object.

(II). The distance of the image from the mirror will be the same as the distance of the object from the mirror.

(III). The image form will be virtual.

(IV). The image form will be upright.

the position of image related to the position of the object

The image is as far behind the mirror as the object is in front of it i.e, the perpendicular distance of image from the mirror is equal to the perpendicular distance of object from the mirror.