Question

mx-my=m²+n² x+y=2mn
Factorise it.​
Pls do it fast

Answer 1

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mx-ny = m²+n²

⇒ mx - ny = m² + n² +2mn - 2mn

⇒ mx - ny = (m + n)² - 2mn [identity a² + 2ab +b² = (a+b)²] → 1

x + y = 2m → 2

Substituting eq. 2 in eq. 1.

mx - ny = (m + n)² - (x + y)n

- (x + y)nmx - ny = (m + n)² - nx - ny

Addding ny to both sides, you get:

Addding ny to both sides, you get:mx = (m + n)² - nx

- nxmx + nx = (m + n)²

x(m + n) = (m + n)²

Dividing both sides by (m + n), you get:

Dividing both sides by (m + n), you get:x = m + n

Dividing both sides by (m + n), you get:x = m + nSubstituting x = m + 2 in eq. 1.

Dividing both sides by (m + n), you get:x = m + nSubstituting x = m + 2 in eq. 1.(m + n) + y = 2m

y = 2m - m - n

y = 2m - m - ny = m - n

Therefore, x = m + 2, y = m - n

i hope this helps uhh

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Answer 2

Answer:

actually I don't know

Step-by-step explanation:

sorryyyyy