mx2-9mx+5m+1>0 then m lies in interval
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mx² - 9mx + 5m+1 > 0
As the expression (mx² - 9mx + 5m+1) never becomes 0, it doesn't have a solution.
So (9m)² - 4(m)(5m+1) < 0 (b²-4ac<0 for no solution)
⇒81m² -20m² - 4m < 0
⇒61m² -4m < 0
⇒m(61m - 4) < 0
⇒ m>0 and m<4/61
Thus range of m is (0,4/61)
As the expression (mx² - 9mx + 5m+1) never becomes 0, it doesn't have a solution.
So (9m)² - 4(m)(5m+1) < 0 (b²-4ac<0 for no solution)
⇒81m² -20m² - 4m < 0
⇒61m² -4m < 0
⇒m(61m - 4) < 0
⇒ m>0 and m<4/61
Thus range of m is (0,4/61)
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