mx³y - nxy³ + 2mx² - 2ny²
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mx³y - nxy³ + 2mx² - 2ny². 1. See answer. Add answer+8 pts. jozishaikh403 avatar. Given: 2x2+mxy+3y2−5y−2 has two rational factors ⇒ it can be ...
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Answer: [xy+2] [mx² - ny²]
Regroup the terms
[mx³y - nxy³] + [ 2mx² - 2ny²]
Take out the common factors
xy[mx² - ny²] + 2[mx² - ny²]
[xy+2] [mx² - ny²]
[xy+2] [mx² - ny²]
Hope this helps..
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