Math, asked by sureshpaljayswp768nm, 1 year ago

my father is 5 times as old as his son after 6 years he will be thrice of his son's age find their present age

Answers

Answered by Anonymous
61
Hi.

Good question... Keep Progressing...

Here is your answer---

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Let the Present age of the Son be x years.
Therefore, Present Father's age = 5x.

After 6 years,
           Son's age = (x + 6) years.
       Father's age = (5x + 6)years.

According to the question,
        Father's age {After 6 years} = 3 (x +6)
                             5x +6 = 3x + 18
                              5x - 3x = 18 - 6
                                    2x  = 12
                                       x = 6 years
                               ------------------------------
Thus,
Present age of Son = x years.
Present age of son = 6 years.

Present age of Father = 5x
Present age of Father = 5 * 6
                                      = 30 years.

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Hope it helps.

Have a nice day.

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Answered by HarishAS
12
Hi friend, Harish here.

Here is your answer;

Given that:

1) Father's age is 5 times his son .

2) And Father's age will be thrice his son's age after 6 years.

To find.

The present age of his son.

Solution:

Let Present Age of father be ' x ' & Age of his son be ' y '.

Then,

 x =  5\times y               -  (i)

After six years their age will be " x + 6 " & " y + 6" respectively.

⇒ (x+6) = 3(y+6)

⇒ x + 6 = 3y + 18

⇒ x = 3y +18-6 = 3y+12          - (ii)

Now by equating x from equation (i) & (ii) we get. 

⇒ 5y = 3y+12

⇒ 5y - 3y =12

⇒ 2y = 12

⇒  \blod{y= \frac{12}{2} = 6}

Therefore present age of the son is 6 years.

We know that,

Age of father  = 5 y 
 
                       = 5 × 6  
 
                       = 30 years.

Therefore present age of father is 30 years.
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Hope my answer is helpful to you
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