My mom was of my present age 20 years back. After 30 years, I would be twice as old as I am today. After how many years, the difference between our ages would be a quarter of my then age?
Answers
Answered by
7
Answer:
50
Explanation:
My age be x yrs. and mom's age is x+20 yrs.
After 30yrs,I will be (x+30)yrs.
Then x+30=2x
Then x=30.
Their age difference =20 yrs
Then,(x+50)÷4=(30+50)÷4=80÷4=20
Then,after 50 yrs.,the difference between our ages would be quarter of my age.
Answered by
0
Given:
Mom's present = 20 yrs
After 30 yrs it would twice as old as today.
To Find:
After how many years, the difference between our ages would be a quarter of my then age.
Explanation:
Let my age be x yrs.
Then my mom's age would be (x+20)yrs.
Then after 30yrs it would be (x+30)
x + 30 = 2x
x=30
Age difference = 20 yrs
(x+50)/4
=(30+50)/4
=80/4
=20
Then after 50 yrs the difference between of age will be 1/4 of my age.
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