My mother is 12 years more than twice my age. After 8 years my mother's age will be 20 years less than three times my age. Find my age and mother age?
Answers
Answered by
20
let my age be x
my mother's age=12+2x
after 8 years
my age = x+8
my mother's age = 12+8+2x = 20+2x
mother's age given = 20-3x
so, 20+2x = 20-3x
2x +3x=20-20
5x=0
x=0\5=0
so x=0
12+2x=12+2*0=12
so when you will be of 0 years,then your mother's age will be 12
my mother's age=12+2x
after 8 years
my age = x+8
my mother's age = 12+8+2x = 20+2x
mother's age given = 20-3x
so, 20+2x = 20-3x
2x +3x=20-20
5x=0
x=0\5=0
so x=0
12+2x=12+2*0=12
so when you will be of 0 years,then your mother's age will be 12
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Answered by
3
Answer:
et my age be x
my mother's age=12+2x
after 8 years
my age = x+8
my mother's age = 12+8+2x = 20+2x
mother's age given = 20-3x
so, 20+2x = 20-3x
2x +3x=20-20
5x=0
x=0\5=0
so x=0
12+2x=12+2*0=12
so when you will be of 0 years,then your mother's age will be 12
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