My mother is 12 years more than twice my age. After 8 years, my mother’s age will be 20 years less than three times my age. Find my age and my mother’s age.
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Answered by
2
Let 'm' be the age of mother and 'k' be the age of the kid.
Given : m = 2k + 12 -------eq.1
After 8 years ,
m' = m + 8 , k' = k +8
m' = 3k' - 20 = 3(k + 8) - 20 = 3k + 4 = m + 8
m = 3k - 4 ------------eq.2
put eq.2 in eq.1
3k - 4 = 2k + 12
k = 16
m = 4
Given : m = 2k + 12 -------eq.1
After 8 years ,
m' = m + 8 , k' = k +8
m' = 3k' - 20 = 3(k + 8) - 20 = 3k + 4 = m + 8
m = 3k - 4 ------------eq.2
put eq.2 in eq.1
3k - 4 = 2k + 12
k = 16
m = 4
Answered by
1
Answer:
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Step-by-step explanation:
Let my age be x
my mother's age=12+2x
after 8 years
my age = x+8
my mother's age = 12+8+2x = 20+2x
mother's age given = 20-3x
so, 20+2x = 20-3x
2x +3x=20-20
5x=0
x=0\5=0
so x=0
12+2x=12+2*0=12
so when you will be of 0 years,then your mother's age will be 12
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