Question

My question is 92 and 404 HCF what answer ​

Answer 1

Answer:

HCF of 92 and 404 is 4

Step-by-step explanation:

We can find the HCF by using Euclid's division algorithm:

=> 404 = 92 * 4 + 36

=> 92 = 36 * 2 + 20

=> 36 = 20 * 1 + 16

=> 20 = 16 * 1 + 4

=> 16 = 4 * 4 + 0

∴ HCF of 92 and 404 is 4

                OR

By prime factorization:

Prime factorization of 404 =  2 * 2 * 101

Prime factorization of 92 = 2 * 2 * 23

Common factors taken outside from prime factors we get = 2 * 2 = 4

∴ HCF of 92 and 404 is 4 by using this method also.

Answer 2

$\sf\underline{ \: By \: using \: Euclid's \: algorithm \: \: \: </p><p>}$

Since , 404 > 92

$\star$We apply the division lemma to 404 and 92 , to get

$\to$404 = 92 × 4 + 36

$\star$Since , the remainder 36 ≠ 0 , we apply the division lemma to 92 and 36

$\to$92 = 36 × 2 + 20

$\star$We consider the new divisor 36 And the new remainder 20 , and apply the division lemma to get

$\to$36 = 20 × 1 + 16

$\star$We consider the new divisor 20 and the new remainder 16 , and apply the division lemma to get

$\to$20 = 16 × 1 + 4

$\star$We consider the new divisor 16 and the new remainder 4 , and apply the division lemma to get

$\to$16 = 4 × 4 + 0

The remainder has now become zero , so our procedure stops . since the divisor at this stage is 4

$\therefore$The HCF of 404 And 92 is 4