Question

3. A car moving with uniform velocity 72 km/h
suddenly stops by applying brakes which covers
distance of 50 m after applying brakes. Calculat
the retardation.​

Answer 1

Answer:

$2as = {v}^{2} - {u}^{2} \\ 2a \times 50 = 0 - ( {72 \times \frac{5}{18}) }^{2} \\ a = - \frac{400}{100} = - 4 \: \: \frac{m}{ {s}^{2} }$