Question

my question is. a bus running at a speed of 18 km per hour is stopped at 2.5 seconds by applying brakes calculate the retardation produced

Answer 1

v=om/s
u=18km/hr=5m/s
t=2.5s
a=(v-u)÷t   =-5/2.5   =-2
retardation =$2m/s ^{2}$

Answer 2

Dear Friends,
Speed = 18×(1000÷3600) m/s
= 18×(5÷18) m/s
= 5 m/s
R e t a r d a t i o n = Speed ÷ Time
= 5÷2.5 m/s²
= 2 m/s²
I hope its help u
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