Question

my question is in attachment

Answer 1

$\textbf{Question}$

Find the area of triangle in which ; a = 13 b = 14 c = 15

$\boxed{\textbf{Answer}}$
84${m}^{2}$

$\boxed{\textbf{Formula \:used}}$:- $\dfrac{a+b+c}{2}$

s = $\dfrac{13+14+15}{2}$

s = $\dfrac{42}{2}$

s =21m

$\underline\bold{Note}$a ,b, c are the sides of triangle and s defines semi perimeter

Using of herons formula ..
= >√s (s - a) (s - b) (s - c)

PUTTING OF VALUES IN THE GIVEN FORMULA .

= >√21 (21 - 13) (21 - 14) (21 - 15).

= >√21 (8)(7)(6)

= >√7056

= >√ 84 × 84

${84m}^{2}$

Answer 2

Heya......


In Heron's Formula there "S" is given .. S=Sum of all sides of triangle/2...i.e., S

And then the value of s put in the Heron's Formula along with the value of sides of triangle i.e., "a", "b", "c"...

And then by evaluating we found the answer is 84m².