Question

My question is in the attachment

Answer 1

$\mathfrak{ \huge{ \pink{ \underline{Answer}}}} \\ \\ \bigodot \: \red{given} \\ \\ \implies \: initial \: length = 50m \\ \implies \: initial \: temp. = 303k \\ \implies \: final \: temp. = 323k \\ \implies \: coefficient \: of \: linear \: expansion \: \alpha = 23 \times {10}^{ - 6} \\ \implies \: change \: in \: temp. = 323 - 303 = 20k \\ \\ \bigodot \: \red{formula} \\ \\ \implies \: \green{lf = li(1 + \alpha \times \delta \: t)} \\ \implies \: calculate \: by \: given \: values... \\ \implies \: lf = 50.023m \\ \\ \implies \: so \: final \: length \: of \: aluminium \: rod \: \boxed{ \boxed{ \blue{lf = 50.023m}}}$