my thousand digit is 2 more than my tens digit my hundred digit is 3 more than my tens digit and my ones digit is 2 less than my hundred digit if my ten digit is 5 what number am i
Answers
Answer:
Let’s set each digit equal to a variable:
x = thousands digit
y = hundreds digit
z = tens digit
a = ones digit
From the statement in your question we are given the following equations:
x = 2a
y = a+2
z = x-y
Since z = x-y, the following statement is true:
z = 2a-(a+2)
z = 2a-a-2
z = a-2
So x = 2a, y = a+2, and z = a-2. The only variable we don’t have a value for is a. If we find that we can find the value of each other variable.
There is a critical restriction on what each variable can be: since we are using the base-10 numbering system that means there are only 10 possible values for each variable. X cannot be equal to zero because that means we would have a 3-digit number when the question says we have a 4-digit number.
since x = 2a, a would have to be either 4, 3, 2, or 1 as this would make x equal to 8, 6, 4, or 2, respectively, and fulfill the restriction. There is another restriction, too, and that is for z:
z = a-2
the result of that equation is that z could be equal to 0, which would make a equal to 2, but a cannot be equal to 1 because that would make z negative.
This narrows down the possible values for a to just 2, 3, or 4
So let’s try this with a = 2:
x = 2a
x = 2*2
x = 4
y = a+2
y = 4
z = a-2
z = 2–2
z = 0
So if a = 2, then x = 4, y = 4, and z = 0
The number would be 4,402
Do the other possible values work…? Let’s try a = 3
a = 3
x = 2a
x = 2*3
x = 6
y = a+2
y = 3+2
y = 5
z = a-2
z = 3–2
z = 1
Answer:
The required number = 7856
Step-by-step explanation:
Let x,y,z,w be the thousands, hundreds, tens and one's digit respectively
By the given conditions
The thousand's digit is 2 more than the tens digit, we have
x = 2+z ----------------(1)
The hundred digit is 3 more than tens digit
y = 3 +z ---------------(2)
Ones digit is 2 less than hundred digit
w = y -2 ---------------(3)
Ten's digit of the number = z = 5
From equation (1) we have
Thousand's digit x = 2 + z = 7
From equation (2) we have
Hundred's digit =y = 3 +z = 3+5 = 8
From equation (3)
ones digit = w = y -2 = 8 -2 = 6
∴ x = 7 , y = 8 , z = 5 , w = 6
∴ The required number = 7856
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