(n-10)(n-10)+(10-n) factorize the following equation
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(n-10)(n-10)+(10-n)
=(n-10)² +(10-n)
=(n² + 10² -2×n×10)+(10-n)
=n² + 100 -20n + 10 -n
=n²-21n+110
=n² -11n -10n + 110
=n(n-11) -10(n-11)
=(n-11)(n-10)
=(n-10)² +(10-n)
=(n² + 10² -2×n×10)+(10-n)
=n² + 100 -20n + 10 -n
=n²-21n+110
=n² -11n -10n + 110
=n(n-11) -10(n-11)
=(n-11)(n-10)
Aayush11111:
thanks for the answer
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