N/10 Naoh solution
ph value
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[OH-] = Normality = 0.1
pOH = -log[OH-]
= -log(0.1)
= 1
pH = 14 - pOH
= 14 - 1
= 13
pH of N/10 NaOH solution is 13
pOH = -log[OH-]
= -log(0.1)
= 1
pH = 14 - pOH
= 14 - 1
= 13
pH of N/10 NaOH solution is 13
akshay131:
kese kiya ?
to find the pOH the negative log of 0.1 is taken and then ph
how to find pOH
pehla step kiya hai na
negative log
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