n=10
while n<5:
print(n+n)
n+=10
print(“Program done”)
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Answer:
#include <iostream>
#include <iostream>int main(){
#include <iostream>int main(){ using namespace std;
#include <iostream>int main(){ using namespace std; int n = 1;
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl;
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++;
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++; }
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++; } return 0;
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++; } return 0;}
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++; } return 0;}Output
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++; } return 0;}OutputIn our example, firstly, we assigned a value 1 to a variable 'n'.
#include <iostream>int main(){ using namespace std; int n = 1; while( n <= 10){ cout << n << endl; n++; } return 0;}OutputIn our example, firstly, we assigned a value 1 to a variable 'n'.while(n <= 10) - checks the condition 'n <= 10'. Since the value of n is 1 which is less than 10, the statements within the braces { } are executed.
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