Question

(n+2)!=60[(n-1)!] find n

Answer 1

(n+2)!
=(n+2)(n+1)(n)(n-1)!
(n+2)!=60[(n-1)!]
(n+2)(n+1)(n)(n-1)!=60[(n-1)!]
(n+2)(n+1)(n)=60
(n+2)(n+1)(n)=5*4*3
(n+2)(n+1)(n)=(3+2)(3+1)(3)
On comparing both side
n=3
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