n^2>=n prove that when n>=1
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Solution :
We can prove it using the method of Induction.
Step 1.
When n = 1,
1² = 1
i.e., the given statement holds for n = 1
Step 2.
When n = 2,
2² = 4 > 2
When n = 3,
3² = 9 > 3
and so on
i.e., the given statement holds for n = 2, 3, ...
Step 3.
Let, the given statement holds for n = k (> 0)
Then, k² > k
Now, (k + 1)² - (k + 1)
= k² + 2k + 1 - k - 1
= k² + k + 1
> 2k + 1 , as k² > k
> 0, as k > 0
i.e., (k + 1)² - (k + 1) > 0
i.e., (k + 1)² > k + 1
Thus the statement holds for n = k + 1 whenever n = k holds.
Therefore, by method of Induction, we can conclude that n^2 ≥ n for all n ≥ 1
Note : We have only solved it for n as a Natural number. However you can try proving it for any real number.
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