Question

n/3 + 1 = 4 - n
solve linear equation class 6th​

Answer 1

Step-by-step explanation:

$\frac{n}{3} + 1 = 4 - n \\ \frac{n + 3}{3} = 4 - n \\ \frac{n + 3}{3} + n = 4 \\ \frac{n + 3 + 3n}{3} = 4 \\ 4n + 3 = 12 \\ 4n = 9 \\ n = \frac{9}{4}$

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Answer 2

Answer:

By rearranging the terms

n/3-n=4-1

n+3n

______ = 3

3

4n= 3×3

4n=9

n= 9/4