Question

n(3^-5)=3 find n value

Answer 1

Given question is..

=) n(3^-5) =3

=) n = 3/3^-5

=) n = 3 ^(1+5) { a^m/ a^n = a^(m-n)}

=) n = 3^6 = 729 ans..

Answer 2

N ( $3^{-5}$ ) = 3

N = $\frac{3}{ 3^{-5} } \\ = \frac{ 3^{1} }{ 3^{-5} }$


$\frac{ a^{m} }{ a^{n} } } = a ^{(m-n)}$

Therefore :

N = $3^{ 1 - [-5 ]}$

N = $3^{ 1+ 5}$

N = 3⁶

N = 729