Math, asked by vibhu95, 1 year ago

(n-3!) by(n-5!) ko kaise solve kre​

Answers

Answered by jinadevkv
1

(n-3)!/(n-5)! = (n-3)(n-4)(n-5)!/(n-5)! = (n-3)(n-4) = n² - 4n -3n +(-3*-4)

= n² - 7n + 12

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