n^5/5+n^3/3+7n/15 prove that it is a natural no.
plz answer it fast
Answers
Hello friends.
Good ol' induction works too:
3+5+7 = 15 [ n=1 case ]
Suppose 3n5 + 5n3 + 7n is divisible by 15.
The (n+1) case is
3 (n+1)5 + 5 (n+1)3 + 7 (n+1) .
Expanding this out will give you 3n5 + 5n3 + 7n plus terms with coefficients that are all multiples of 15... with the constant terms being 3+5+7 .
(But the "Little Theorem" proof is cooler...)
hope it's helpful for you...
❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Step-by-step explanation:
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closing bracket edit kardena sis