n(A) =10 and n(A intersection B) =3,find n((A intersection B)' intersection A)
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Given: n(A) =10 and n(A intersection B) =3
To Find: n((A intersection B)' intersection A)
Solution:
According to De Morgan's first law, the complement of the union of two sets A and B is equal to the intersection of the complement of the sets A and B.
Where A' denotes the complement.
It can be represented as (A ∪ B)' = A' ∩ B'.
n(A U B) = 10
n( A ∩ B) = 3
Therefore, n((A intersection B)' intersection A)
= 10-3
= 7
Therefore, n((A intersection B)' intersection A) is 7.
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