n(A - B) is equal to: *
n(A) – n(A⋃B)
n(A) – n(A∩B)
n(B) – n(A∩B)
n(ξ) – n(A⋃B)
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Answered by
6
Answer:
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Answered by
4
Answer:
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)Given n(A)=7
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)Given n(A)=7n(B)=9
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)Given n(A)=7n(B)=9n(A∪B)=14
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)Given n(A)=7n(B)=9n(A∪B)=14Substituting in 1
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)Given n(A)=7n(B)=9n(A∪B)=14Substituting in 114=7+9−n(A∩B)
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)Given n(A)=7n(B)=9n(A∪B)=14Substituting in 114=7+9−n(A∩B)⇒n(A∩B)=16−14=2
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