Math, asked by KunalTheGreat, 1 year ago

n a bookshop, small photo albums and big photo albums were wrapped in bundles of 5 albums and 3 albums respectively. Each bundle of small photo albums had a width of 8 cm and each bundle of big photo albums had a width of 12 cm. The photo albums were arranged from one end to the other end of a shelf with no gap as shown below.



There were 54 more small photo albums than big photo albums on the shelf. How many photo albums were there altogether?

Attachments:

Anonymous: Is it right?
KunalTheGreat: yep
KunalTheGreat: no wait
KunalTheGreat: no it's 126
Anonymous: Check it again it is 270
Anonymous: wait. !!!!
Anonymous: Yes its 126 ,
KunalTheGreat: see..
Anonymous: some calc mistake arrived
KunalTheGreat: hmm..

Answers

Answered by Anonymous
2
Hey bro! here is your answer!

Let the lenght of shelf be 'l' cm.

Then,
According to the question ,
No. of bundle of small photo albums = l/ 8.

No. of small photo albums =( l/8 )* 5

Similarly,
No. of big photo albums = l/ 12 *3 = l/4

Now,
Acvording to last three lines of questions,

No. of big albums- No. of small albums = 54

( l/8)*5-l/4 = 54
=> 3l/8 = 54
=>l = 144cm.

Total no. of albums = No. of small albums + No. of big albums
= 5l/8+ l/4
= (5/8 ) * 144+ 144/4
=90+36
=126


Hope, you understand my answer and it may helps you.

KunalTheGreat: tnx
Anonymous: wlcm bro!
RadhikaSahni: nice
Anonymous: Thanks Radhika !
Anonymous: Thanks for marking me Brainliest
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