n a bookshop, small photo albums and big photo albums were wrapped in bundles of 5 albums and 3 albums respectively. Each bundle of small photo albums had a width of 8 cm and each bundle of big photo albums had a width of 12 cm. The photo albums were arranged from one end to the other end of a shelf with no gap as shown below.
There were 54 more small photo albums than big photo albums on the shelf. How many photo albums were there altogether?
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Hey bro! here is your answer!
Let the lenght of shelf be 'l' cm.
Then,
According to the question ,
No. of bundle of small photo albums = l/ 8.
No. of small photo albums =( l/8 )* 5
Similarly,
No. of big photo albums = l/ 12 *3 = l/4
Now,
Acvording to last three lines of questions,
No. of big albums- No. of small albums = 54
( l/8)*5-l/4 = 54
=> 3l/8 = 54
=>l = 144cm.
Total no. of albums = No. of small albums + No. of big albums
= 5l/8+ l/4
= (5/8 ) * 144+ 144/4
=90+36
=126
Hope, you understand my answer and it may helps you.
Let the lenght of shelf be 'l' cm.
Then,
According to the question ,
No. of bundle of small photo albums = l/ 8.
No. of small photo albums =( l/8 )* 5
Similarly,
No. of big photo albums = l/ 12 *3 = l/4
Now,
Acvording to last three lines of questions,
No. of big albums- No. of small albums = 54
( l/8)*5-l/4 = 54
=> 3l/8 = 54
=>l = 144cm.
Total no. of albums = No. of small albums + No. of big albums
= 5l/8+ l/4
= (5/8 ) * 144+ 144/4
=90+36
=126
Hope, you understand my answer and it may helps you.
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