n a box, there are 8 red, 7 blue and 6 green balls. one ball is picked up randomly. what is the probability that it is neither red nor green?
Answers
Answered by
3
----------------------------------------
Here is the solution:
----------------------------------------
Find the total number of balls:
Total number of balls = 8 + 7 + 6 = 21
Find the total number of balls that is neither red nor green:
Neither red nor green = blue = 7
Find the probability that it is neither red nor green:
P(neither red nor green) = 7/21 = 1/3
Answer: The probability is 1/3
Similar questions