Math, asked by ritikg5271, 1 year ago

n a box, there are 8 red, 7 blue and 6 green balls. one ball is picked up randomly. what is the probability that it is neither red nor green?

Answers

Answered by TooFree
3

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Here is the solution:

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Find the total number of balls:

Total number of balls = 8 + 7 + 6 = 21


Find the total number of balls that is neither red nor green:

Neither red nor green = blue = 7


Find the probability that it is neither red nor green:

P(neither red nor green) = 7/21 = 1/3


Answer: The probability is 1/3

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