Question

n a Millikan's oil drop experiment, a drop is observed to fall with a terminal speed 1.4 mm s7 in the absence of electric filed. When a vertical electric field of 4.9 x 105 V m1 is applied, the droplet is observed to continue to move downward at a lower terminal speed 1.21 mm s 1. Calculate the charge on the drop. (density of oil = 750 kg m3, viscosity of air = 1.81 x10-5 kg m s 1, density of air = 1.29 kg m']

Answer 1

Explanation:

Millikan's oil drop experiment measured the charge of an electron. ... Electrically charged oil droplets entered the electric field and were balanced between two plates by altering the field. When the charged drops fell at a constant rate, the gravitational and electric forces on it were equal

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