Question

N archer pulls an arrow in his bow to a distance of 0.5m against a force of 150n. what is the potential energy gained?

Answer 1

Given :

• Distance (s) = 0.5 m
• Force (F) = 150 N

To Find :

• Potential Energy Gained

Solution :

We are given Force with which the archer pulls an arrow from her bow, and also the distance stretching is 0.5 m.

Here, work done is stored as Potential Energy

$\implies \sf{Work \: Done \: = \: Potential \: Energy} \\ \\ \implies \sf{P.E \: = \: Work \: Done \: = \: F.s} \\ \\ \implies \sf{P.E \: = \: F.s}$

Where,

• P.E is Potential Energy
• F is Force with which arrow is pulled from now
• s is distance

$\implies \sf{P.E \: = \: 150 \: \times \: 0.5} \\ \\ \implies \sf{P.E \: = \: 75}$

$\therefore$ Potential Energy gained is 75 Joules