'n' equal resistors are connected in series and then parallel. Find the ratio of their equivalent resistor?
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Answer:n^2:1 in case ratio is taken series :parallel
Explanation:
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Answer:
Rsquare:1 is the ratio
Explanation:for series
Equivalent resistanceis = n*r
For parallel it is(1/r+1/r ....) n times
Thus Equivalent is n/r
nr/(n/r)= r^2/1
tthus ratio is r^2
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