n factor of ferrous oxalate with kmno4 in medium containing acid
Answers
Explanation:
An easy one
10 FeC2O4 + 6 KMnO4 + 24 H2SO4 = 3 K2SO4 + 6 MnSO4 + 5 Fe2(SO4)3 + 24 H2O + 10 CO2
Just remember that KMnO4 is a very good oxidizing agent.
Ferrous is oxidized to ferric state
Carbon and hydrogen are converted to CO2 and H2O
All the metallic ions are converted to sulphates
Write the equation keeping in mind that the valency of of iron in ferric state is 3, that of K and Mn is one and two respectively as
FeC2O4 + KMnO4 + H2SO4 = K2SO4 + MnSO4 + Fe2(SO4)3 + H2O + CO2
FeC2O4 is oxidized and KMnO4 is reduced. Hence the main reaction is
Fe2+ → Fe3+ (removal of 1 electron)
Mn7+ → Mn 2+ (addition of 5 electrons)
In order to balance multiply (Fe2+ → Fe3+) by 5
Now you know that there should be 5 FeC2O4 molecules. Write that and balance the rest.