Question

N-factor of K2Cr2O7 in an acidic medium. With explanation.

Answer 1

Answer:

n-factor of k2cr2o7 in acidic med? n-factor can be simply defined as the change in the oxidation state of a particular ion. ... Cromate ion is changing from +6 oxidation state to +3 oxidation state. In other words, this reaction involves the exchange of 6 electrons, hence the n factor is 6

Explanation:

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Answer 2

Answer:

n-factor can be simply defined as the change in the oxidation state of a particular ion. This will be equal to the number of N-Factor

Chromium is hexavalent in this compound - each one has an oxidation state of +6 to balance out the 7 x-2 oxygen ions and the 2 x +1 potassium ions (the net total has to be zero for a neutral compound). oxidation state of Cr in K2Cr2O7 is +6.