Question

Q2 If the zeroes of the given
polynomial are 2 and -3,then:
x2 + (a + 1) x + b
a=-7,b=-1
a=2,b=-6
a=5,b=-1
a=0,b=-6​

Answer 1

$a' = 1 \\b' = a + 1 \\c = b\\\alpha = 2\\\beta = -3\\\\\alpha +\beta =2+(-3) = -1 \\\alpha +\beta= \frac{-b'}{a'} = \frac{-(a + 1)}{1} =-(a + 1)\\-1 = -a - 1\\a = -1 + 1\\\\a = 0\\\alpha \beta =2*-3 = -6 \\\alpha \beta = \frac{c}{a'} = \frac{a}{1} \\-6=b$

ANSWER : -

Option 4

Answer 2

Answer:

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Step-by-step explanation:

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