Question

n-heptane on monochlorination gives a number of isomers.How many of them are optically active​

Answer 1

Explanation:

Now circled carbon are chiral (optically active ) each compound having 1 optically active carbon has 2 isomers (1 for each r and s) and for a compound having 2 chiral centres have 4 isomers . So like this total 11 isomers are possible out of which 8 are optically active

Answer 2

Answer:

Now circled carbon are chiral (optically active ) each compound having 1 optically active carbon has 2 isomers (1 for each r and s) and for a compound having 2 chiral centres have 4 isomers . So like this total 11 isomers are possible out of which 8 are optically active.