Question

N is a four digit number. If the leftmost digit is removed, the resulting three digit number is 1/9th of n. How many such n are possible?

Answer 1

Let x∈[1,9] denote the leftmost digit.

Let y∈[000,999] denote the remaining digits.

1000x+y=9y⟹1000x=8y⟹125x=y.

Answer 2

Answer:

7

how can 7 I don't understand but 7 is the right answer that I know