n is a natural number and (n+4) (n+4) is odd then find the biggest power of 2 that divides (n+1) (n+3) for any n
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Step-by-step explanation:
=> 1^n + 2^n + 3^n + 4^n will be divisible by 5 when n is odd. Last digit of 1^n + 2^n + 3^n + 4^n will be the last digit of 1 + 4 + 9 + 6 = 0 when n is of the format of 4k + 2. T => 1^n + 2^n + 3^n + 4^n will be divisible by 5 when n is odd.
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