Question

n + l = 5
m = 0 , ± 1
s = ± 1 /2
The maximum number of electrons of an atom of chromium that will have the above set of quantum number in its ground state iS?

Answer 1

Answer:

3 electrons

Explanation:

First write electronic configuration of Chromium

1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5

Now l for s orbital is 0 , for p is 1, for d is 2

So for 1s. n+l = 1

for 2s n+l = 2

for 2p n+l =3

for 3s n+l= 3

for 3p n+l =4

for 4s n+l= 4

for 3d n+l=5

So we need to look for only 3d electrons

there are 5 electrons in 3d so one in each subshell

m= +l to -l

so for 3d it is -2 to +2

now

dxy dyz. dxz. dx^2-y^2. dz^2

-2. -1. 0. +1. +2

hence 3 electrons have n+l =5

and m= 0, 1

Hope I was able to solve your doubt