Question

n mole each of H2O(g), H2(g) and O2(g) are mixed at a suitable high temperature to attain the equilibrium
2H2O(g) 2H2(g) + O2(g). If y mole of H2O(g) are the dissociated and the total pressure maintained is
P, calculate the Kp.​

Answer 1

your question is -> n mole each of H2O, H2, O2 are taken in closed container at temperature T. if y mole of H2O are disasssociated at equillibrium and equillibrium pressure is P then calculate the value of Kp.

solution : 2H2O ⇔2H2 + O2

at t = 0, n n n

at eq. (n - y) (n + y/2) n + y

so, total no of moles = n - y + n + y/2 + n + y = 3n + y/2

now, let's derive the expression for Kp

= p(H2)² × p(O2)¹ /p(H2O)²

= {P × (n + y/2)/(3n + y/2)}² × {P × (n + y)/(3n + y/2)}¹/{P × (n - y)/(3n + y/2)}².

= P(n + y/2)² × (n + y)/(3n + y/2)(n - y)²

Answer 2

$\huge\bold\purple{Answer:-}$

your question is -> n mole each of H2O, H2, O2 are taken in closed container at temperature T. if y mole of H2O are disasssociated at equillibrium and equillibrium pressure is P then calculate the value of Kp.

solution : 2H2O ⇔2H2 + O2

at t = 0, n n n

at eq. (n - y) (n + y/2) n + y

so, total no of moles = n - y + n + y/2 + n + y = 3n + y/2

now, let's derive the expression for Kp

= p(H2)² × p(O2)¹ /p(H2O)²

= {P × (n + y/2)/(3n + y/2)}² × {P × (n + y)/(3n + y/2)}¹/{P × (n - y)/(3n + y/2)}².

= P(n + y/2)² × (n + y)/(3n + y/2)(n - y)²