n n If S???? ∑ a???? = 1/6 n (2n² + 9n + 13), then ∑ √a????, equals r =1 r =1 (a) n (n+1)/2 (b) n (n+2)/2
(c) n (n+3)/2 (d) n (n+5)/2
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1
a
4
−a
2
+16
a
2
+16=0
a
2
=−16
a=4
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