Question

n the given figure, AOB is a straight line and the ray OC stands on it.If ∠AOC = (2x − 10)° and ∠BOC = (3x + 20)°, find the value of x.Also, find ∠AOC and ∠BOC.



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Answer 1

Answer:

Step-by-step explanation:

By linear pair property,

Angle AOC+ Angle BOC = 180°

(2x-10)° + (3x+20)° = 180°

(2x-10+3x+20)° = 180°

5x+10 =180

5x = 180-10

x = 170/5

Therefore, the value of x is 34.

Therefore,

angle AOC= (2×34-10)°

=(68-10)°

=58°

angle BOC = (3×34+20)°

= (102+20)°

= 122°

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