Question

n the given figure, O is the centre of the circle. AB and CD are two chords of the circle. Also, OM L AB and ON i CD.f OM ON 3 cm and AM = BM =

the 5cm, finc length of the chord CD.​

Answer 1

Answer:

9 cm

Given- AB and CD are two chords of a circle with centre O.

OM⊥AB and ON⊥CD

AM=AN=4.5 cm

OM=ON=2 cm 

Solution-

AM=AN=4.5 cm

∴AB=AM+AN=(4.5+4.5) cm =9 cm

OM and ON are the perpendicular distances of AB and CD respectively.

Since OM⊥AB and ON⊥CD 

Now OM=ON=2 cm

∴AB and CD are equidistant from O.

∴AB=CD

Since chords of a circle, which are equidistant from the centre of the same circle are equal in length.

∴AB=CD=9 cm



Answer 2

Answer:

flfkekg the first to review this article on karna chahiye aur main hi aap ko hun ki nahi ayega

Step-by-step explanation:

f