N. the marks scored by 5 students in a test for 50 marks are 20, 25, 30, 35, 40. find the s.d for the marks. if the marks are converted for 100 marks, find the s.d. for newly obtained
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Given:
The marks scored by 5 students in a test for 50 marks are 20, 25, 30, 35, 40.
To Find:
Standard deviation in this case and Standard deviation if the marks are converted for 100 marks.
Calculation:
Mean, x = (20 + 25 + 30 + 35 + 40)/5 = 150/5 = 30
Standard deviation = √∑(Xi - x)²/N
⇒ σ = √{(20 - 30)² + (25 - 30)² + (30 - 30)² + (35 - 30)² + (40 - 30)²}/5
⇒ σ = √{10² + 5² + 0 + 5² + 10²}/5
⇒ σ = √{100 + 25 + 25 + 100}/5
⇒ σ = √250/5
⇒ σ = √50
⇒ σ = 7.07
- So the standard deviation is 7.07
- To convert these marks from 100, each value is doubled.
- When each value is multiplied by a no, then the value of standard deviation also gets doubled
⇒ New standard deviation, σ' = 2 × 7.07 = 14.14
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