Question

n(U) = 70 n(A) = 58 n(B) = 32 n(AUB)’ = 6. Find :- a) n(A∩B) b) n(A – B) c) n(AUB) = d) n(A’∩B)

Answer 1

Hii dear,

Given-

n(U)=70

n(A)=58

n(B)=32

n(AUB)’=6

Solution-

Using formulas for operation on sets-

a)n(A∩B)

n(A∩B) = n(A)+n(B)−n(U)+n(AUB)’

n(A∩B) = 58+32-70+6

n(A∩B) = 26

b)n(A-B)

n(A-B) = n(A)-n(A∩B)

n(A-B) = 58-26

n(A-B) = 32

c)n(AUB)

n(AUB) = n(U)-n(AUB)’

n(AUB) = 70-6

n(AUB) = 64

d)n(A’∩B)

n(A’∩B) = n(B)-n(A∩B)

n(A’∩B) = 32-26

n(A’∩B) = 6

Thanks for asking...

Answer 2

In the attachment I have answered this problem.

The solution is simple and easy to understand

See the attachment for detailed solution