Math, asked by Akshaysaisuthari2006, 1 month ago

n(x) = 1/n * (sin^n x + cos^n x) , where x in mathbb R , n >= 1 , then Q: sqrt(2) * f_{1} * (pi/4) - 2f_{2} * (pi/2) + 4 * f_{4}(\pi) = (A) 1 (B) 2 (C) 3​

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Answered by Anonymous
2

n(x) = 1/n * (sin^n x + cos^n x) , where x in mathbb R , n >= 1 , then Q: sqrt(2) * f_{1} * (pi/4) - 2f_{2} * (pi/2) + 4 * f_{4}(\pi) = 2

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