Question

N2 + 3H2---->2NH3, molecular weight of NH3
and N2 are X1 and X2 their equivalent weight are Y1
and Y2, then (Y1 - Y2) is
(1) (2X1 - X2)/6
(2) (X1 - X2)
(3) (3X1 – X2)
(4) (X1- 3X2)​

Answer 1

Answer:

Since the molar mass of the NH3 is X1 then the equivalent weight of NH3 can be found by.

Since, the equivalent weight of H2 is 1 and then the eq. H2 = NH3 so we can write that (3*2)/1 = 2/Y1 hence, Y1 is X1/3 so the weight or the equivalent weight of the N2 will be X2/6 from the above solution we will get.

So, Y1-Y2 will be X1/3 - X2/6 which on solving we will get that (2X1 - X2)/6.

Answer 2

here first we have to find n factor