Question

(n²-4n) (n²-40-1)-20.​

Answer 1

Answer:

${n}^{4} - 4 {n}^{3} - 40 {n}^{2} + 160n - {n}^{2} + 4n - 20 \\ {n}^{4} - 4 {n}^{3} - 41 {n}^{2} + 164n - 20$