n²-(n+1)²-(n+2)²+(n+3)
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n² - (n²+2n+1) - (n²+4n+4) + n+3
= n² - n² - 2n- 1 - n² - 4n - 4 + n+ 3
= -n² - 5n - 2
= n² - n² - 2n- 1 - n² - 4n - 4 + n+ 3
= -n² - 5n - 2
sudhansu4:
A(0) , B(4) ,C(2) , D(6)
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i am sorry my question is wrong correct questin is n²-(n+1)²-(n+2)²+(n+3)²
please solve this question
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Hello Dear!!!
here's your answer...
n²-(n+1)²-(n+2)²+(n+3)
refer the attachment...
here's your answer...
n²-(n+1)²-(n+2)²+(n+3)
refer the attachment...
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nenu topper enti andi.. meere topper
thanku so much
edit cheyyadaniki option ledu andi.. lekapothe chesevadini.. meeku kuda same problem aa
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