Question

N2 + O2↔️2NO Kc = 0.1 at 2000 degree. If original concentration of N2 and O2 were 0.1M each. calculate the concentration of NO at equilibrium​

Answer 1

Answer:

The concentration of NO at equilibrium is 3.16 * 10⁻² M.

Explanation:

Given data:

In the given reaction

N₂ + O₂ ↔️2NO

The equilibrium constant, Kc = 0.1 at 2000℃

[ N₂ ] = 0.1 M or 0.1 mol/L

[ O₂ ] = 0.1 M or 0.1 mol/L

To find: concentration of NO at equilibrium

We know that the formula for equilibrium constant is given by,

Kc = [NO]² / [N2] [O2]

Substituting the given values we get ,

0.1 = [NO]^2 / [0.1 * 0.1]

or, [NO] = √(0.1 * 0.1 * 0.1)

or, [NO] = 0.0316 M = 3.16 * 10⁻² M