Question

n²-tn+1/4 be a perfect square,them value of t are

Answer 1

n^2 - tn +1/4 is perfect square of
( n - 1/2)^2
so value of t = 1

Answer 2

for a quadratic equation to be perfect square,it should have identical roots or solutions.
for identical roots determinant of quadratic equation must be zero
d below is the determinant
$d= {b}^{2} - 4ac$
for quadratic equation
$a {x}^{2} + bx + c$
as per the question,

d=0;
b​2​​−4ac=0
${t}^{2} - 1 = 0$
solving we get
t=1 or -1