Na+ has completely filled K and L shells. Explain
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Answered by
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Nice question..
Here is ur answer :
Na+ has 10 electrons.
In K shell, only 2 electrons exist . So 2 electrons of Na+ take place in K shell. Now 8 electrons remain. In L shell, 8 electrons exist. So last 8 electrons of Na+ take place in L shell.
Therefore, Na+ has completely filled K and L shells.
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@sunita
Nice question..
Here is ur answer :
Na+ has 10 electrons.
In K shell, only 2 electrons exist . So 2 electrons of Na+ take place in K shell. Now 8 electrons remain. In L shell, 8 electrons exist. So last 8 electrons of Na+ take place in L shell.
Therefore, Na+ has completely filled K and L shells.
HOPE IT HELPS YOU..
REGARDS
@sunita
Cutiepie93:
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Answered by
1
Hlo friend.. Cutiepie Here...
Nice question..
Here is ur answer :
EXPLANATION:
Atomic number of Na ( sodium) is 11.Its electronic configuration is 2,8,1. Plus one charge indicates that sodium loses its one electron from outermost shell.
Removing one electron from outermost shell gives electronic configuration as 2,8. i.e. completely filled K and L shell.
Hence, Na+ has completely filled K and L shells.
Final Answer
Maximum number of electrons in K shell is 2. Maximum number of electrons in L shell is 8.
Electronic configuration of Na+ is 2,8. Hence, Na+ has completely filled K and L shells.
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